3(2x+1)=4(3+x)

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Solution for 3(2x+1)=4(3+x) equation: 



3(2x+1)=4(3+x)

We move all terms to the left:

3(2x+1)-(4(3+x))=0

We add all the numbers together, and all the variables

3(2x+1)-(4(x+3))=0

We multiply parentheses

6x-(4(x+3))+3=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

6x-4x-12+3=0

We add all the numbers together, and all the variables

2x-9=0

We move all terms containing x to the left, all other terms to the right

2x=9

x=9/2

x=4+1/2

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