3(2x+1)=21-3(x+2)

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Solution for 3(2x+1)=21-3(x+2) equation: 



3(2x+1)=21-3(x+2)

We move all terms to the left:

3(2x+1)-(21-3(x+2))=0

We multiply parentheses

6x-(21-3(x+2))+3=0



We calculate terms in parentheses: -(21-3(x+2)), so:

21-3(x+2)

determiningTheFunctionDomain
-3(x+2)+21

We multiply parentheses

-3x-6+21

We add all the numbers together, and all the variables

-3x+15

Back to the equation:

-(-3x+15)



We get rid of parentheses

6x+3x-15+3=0

We add all the numbers together, and all the variables

9x-12=0

We move all terms containing x to the left, all other terms to the right

9x=12

x=12/9

x=1+1/3

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