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3(2x+1)=1/3(6x+9)+4x
We move all terms to the left:
3(2x+1)-(1/3(6x+9)+4x)=0
Domain of the equation: 3(6x+9)+4x)!=0We multiply parentheses
x∈R
6x-(1/3(6x+9)+4x)+3=0
We multiply all the terms by the denominator
6x*3(6x+9)+4x)-(1+3*3(6x+9)+4x)=0
Wy multiply elements
18x^2(6+4x)-(1+9x(6+4x)=0
We calculate terms in parentheses: -(1+9x(6+4x), so:We add all the numbers together, and all the variables
1+9x(6+4x
determiningTheFunctionDomain 9x(6+4x+1
Back to the equation:
-(9x(6+4x+1)
18x^2(4x+6)-(9x(4x+7)=0
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9x(4x+7
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