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3(2x+1)=-3(5x-2)+5x
We move all terms to the left:
3(2x+1)-(-3(5x-2)+5x)=0
We multiply parentheses
6x-(-3(5x-2)+5x)+3=0
We calculate terms in parentheses: -(-3(5x-2)+5x), so:We get rid of parentheses
-3(5x-2)+5x
We add all the numbers together, and all the variables
5x-3(5x-2)
We multiply parentheses
5x-15x+6
We add all the numbers together, and all the variables
-10x+6
Back to the equation:
-(-10x+6)
6x+10x-6+3=0
We add all the numbers together, and all the variables
16x-3=0
We move all terms containing x to the left, all other terms to the right
16x=3
x=3/16
x=3/16
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