3(2x+1)-1=(2x+1)-7/9

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Solution for 3(2x+1)-1=(2x+1)-7/9 equation: 



3(2x+1)-1=(2x+1)-7/9

We move all terms to the left:

3(2x+1)-1-((2x+1)-7/9)=0

We multiply parentheses

6x-((2x+1)-7/9)+3-1=0

We multiply all the terms by the denominator


6x*9)-((2x+1)-7+3*9)-1*9)=0

We add all the numbers together, and all the variables

6x*9)-((2x+1)=0

Wy multiply elements

54x^2=0

a = 54; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·54·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{108}=0$

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