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3(2x+1)+5x-10=4(3x-2)
We move all terms to the left:
3(2x+1)+5x-10-(4(3x-2))=0
We add all the numbers together, and all the variables
5x+3(2x+1)-(4(3x-2))-10=0
We multiply parentheses
5x+6x-(4(3x-2))+3-10=0
We calculate terms in parentheses: -(4(3x-2)), so:We add all the numbers together, and all the variables
4(3x-2)
We multiply parentheses
12x-8
Back to the equation:
-(12x-8)
11x-(12x-8)-7=0
We get rid of parentheses
11x-12x+8-7=0
We add all the numbers together, and all the variables
-1x+1=0
We move all terms containing x to the left, all other terms to the right
-x=-1
x=-1/-1
x=1
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