3(2x+1)+3(2x+1)+7=42-5x

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Solution for 3(2x+1)+3(2x+1)+7=42-5x equation: 



3(2x+1)+3(2x+1)+7=42-5x

We move all terms to the left:

3(2x+1)+3(2x+1)+7-(42-5x)=0

We add all the numbers together, and all the variables

3(2x+1)+3(2x+1)-(-5x+42)+7=0

We multiply parentheses

6x+6x-(-5x+42)+3+3+7=0

We get rid of parentheses

6x+6x+5x-42+3+3+7=0

We add all the numbers together, and all the variables

17x-29=0

We move all terms containing x to the left, all other terms to the right

17x=29

x=29/17

x=1+12/17

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