3(2x+1)+2=(x+3)

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Solution for 3(2x+1)+2=(x+3) equation: 



3(2x+1)+2=(x+3)

We move all terms to the left:

3(2x+1)+2-((x+3))=0

We multiply parentheses

6x-((x+3))+3+2=0



We calculate terms in parentheses: -((x+3)), so:

(x+3)

We get rid of parentheses

x+3

Back to the equation:

-(x+3)



We add all the numbers together, and all the variables

6x-(x+3)+5=0

We get rid of parentheses

6x-x-3+5=0

We add all the numbers together, and all the variables

5x+2=0

We move all terms containing x to the left, all other terms to the right

5x=-2

x=-2/5

x=-2/5

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