3(2x+)=2(x+1)=23

Solution for 3(2x+)=2(x+1)=23 equation:

3(2x+)=2(x+1)=23

We move all terms to the left:

3(2x+)-(2(x+1))=0

We add all the numbers together, and all the variables

3(+2x)-(2(x+1))=0

We multiply parentheses

6x-(2(x+1))=0


We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)


We get rid of parentheses

6x-2x-2=0

We add all the numbers together, and all the variables

4x-2=0

We move all terms containing x to the left, all other terms to the right

4x=2

x=2/4

x=1/2