3(2w+1)=5(w-2)+12

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Solution for 3(2w+1)=5(w-2)+12 equation: 



3(2w+1)=5(w-2)+12

We move all terms to the left:

3(2w+1)-(5(w-2)+12)=0

We multiply parentheses

6w-(5(w-2)+12)+3=0



We calculate terms in parentheses: -(5(w-2)+12), so:

5(w-2)+12

We multiply parentheses

5w-10+12

We add all the numbers together, and all the variables

5w+2

Back to the equation:

-(5w+2)



We get rid of parentheses

6w-5w-2+3=0

We add all the numbers together, and all the variables

w+1=0

We move all terms containing w to the left, all other terms to the right

w=-1

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