3(2v-2)+2v+8=4(v-6)+2v

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Solution for 3(2v-2)+2v+8=4(v-6)+2v equation: 



3(2v-2)+2v+8=4(v-6)+2v

We move all terms to the left:

3(2v-2)+2v+8-(4(v-6)+2v)=0

We add all the numbers together, and all the variables

2v+3(2v-2)-(4(v-6)+2v)+8=0

We multiply parentheses

2v+6v-(4(v-6)+2v)-6+8=0



We calculate terms in parentheses: -(4(v-6)+2v), so:

4(v-6)+2v

We add all the numbers together, and all the variables

2v+4(v-6)

We multiply parentheses

2v+4v-24

We add all the numbers together, and all the variables

6v-24

Back to the equation:

-(6v-24)



We add all the numbers together, and all the variables

8v-(6v-24)+2=0

We get rid of parentheses

8v-6v+24+2=0

We add all the numbers together, and all the variables

2v+26=0

We move all terms containing v to the left, all other terms to the right

2v=-26

v=-26/2

v=-13

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