3(2u-1)+u-2=5(u+2)

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Solution for 3(2u-1)+u-2=5(u+2) equation: 



3(2u-1)+u-2=5(u+2)

We move all terms to the left:

3(2u-1)+u-2-(5(u+2))=0

We add all the numbers together, and all the variables

u+3(2u-1)-(5(u+2))-2=0

We multiply parentheses

u+6u-(5(u+2))-3-2=0



We calculate terms in parentheses: -(5(u+2)), so:

5(u+2)

We multiply parentheses

5u+10

Back to the equation:

-(5u+10)



We add all the numbers together, and all the variables

7u-(5u+10)-5=0

We get rid of parentheses

7u-5u-10-5=0

We add all the numbers together, and all the variables

2u-15=0

We move all terms containing u to the left, all other terms to the right

2u=15

u=15/2

u=7+1/2

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