3(2t-1)+5=5(t+1)

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Solution for 3(2t-1)+5=5(t+1) equation: 



3(2t-1)+5=5(t+1)

We move all terms to the left:

3(2t-1)+5-(5(t+1))=0

We multiply parentheses

6t-(5(t+1))-3+5=0



We calculate terms in parentheses: -(5(t+1)), so:

5(t+1)

We multiply parentheses

5t+5

Back to the equation:

-(5t+5)



We add all the numbers together, and all the variables

6t-(5t+5)+2=0

We get rid of parentheses

6t-5t-5+2=0

We add all the numbers together, and all the variables

t-3=0

We move all terms containing t to the left, all other terms to the right

t=3

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