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3(2s+3)=2(5s-1)
We move all terms to the left:
3(2s+3)-(2(5s-1))=0
We multiply parentheses
6s-(2(5s-1))+9=0
We calculate terms in parentheses: -(2(5s-1)), so:We get rid of parentheses
2(5s-1)
We multiply parentheses
10s-2
Back to the equation:
-(10s-2)
6s-10s+2+9=0
We add all the numbers together, and all the variables
-4s+11=0
We move all terms containing s to the left, all other terms to the right
-4s=-11
s=-11/-4
s=2+3/4
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