3(2r-5)+(r-2)=

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Solution for 3(2r-5)+(r-2)= equation:


Simplifying
3(2r + -5) + (r + -2) = 0

Reorder the terms:
3(-5 + 2r) + (r + -2) = 0
(-5 * 3 + 2r * 3) + (r + -2) = 0
(-15 + 6r) + (r + -2) = 0

Reorder the terms:
-15 + 6r + (-2 + r) = 0

Remove parenthesis around (-2 + r)
-15 + 6r + -2 + r = 0

Reorder the terms:
-15 + -2 + 6r + r = 0

Combine like terms: -15 + -2 = -17
-17 + 6r + r = 0

Combine like terms: 6r + r = 7r
-17 + 7r = 0

Solving
-17 + 7r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '17' to each side of the equation.
-17 + 17 + 7r = 0 + 17

Combine like terms: -17 + 17 = 0
0 + 7r = 0 + 17
7r = 0 + 17

Combine like terms: 0 + 17 = 17
7r = 17

Divide each side by '7'.
r = 2.428571429

Simplifying
r = 2.428571429

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