3(2r-4)-3r=13(r-4)

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Solution for 3(2r-4)-3r=13(r-4) equation: 



3(2r-4)-3r=13(r-4)

We move all terms to the left:

3(2r-4)-3r-(13(r-4))=0

We add all the numbers together, and all the variables

-3r+3(2r-4)-(13(r-4))=0

We multiply parentheses

-3r+6r-(13(r-4))-12=0



We calculate terms in parentheses: -(13(r-4)), so:

13(r-4)

We multiply parentheses

13r-52

Back to the equation:

-(13r-52)



We add all the numbers together, and all the variables

3r-(13r-52)-12=0

We get rid of parentheses

3r-13r+52-12=0

We add all the numbers together, and all the variables

-10r+40=0

We move all terms containing r to the left, all other terms to the right

-10r=-40

r=-40/-10

r=+4

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