3(2r-14)-3r=12(r-4)

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Solution for 3(2r-14)-3r=12(r-4) equation: 



3(2r-14)-3r=12(r-4)

We move all terms to the left:

3(2r-14)-3r-(12(r-4))=0

We add all the numbers together, and all the variables

-3r+3(2r-14)-(12(r-4))=0

We multiply parentheses

-3r+6r-(12(r-4))-42=0



We calculate terms in parentheses: -(12(r-4)), so:

12(r-4)

We multiply parentheses

12r-48

Back to the equation:

-(12r-48)



We add all the numbers together, and all the variables

3r-(12r-48)-42=0

We get rid of parentheses

3r-12r+48-42=0

We add all the numbers together, and all the variables

-9r+6=0

We move all terms containing r to the left, all other terms to the right

-9r=-6

r=-6/-9

r=2/3

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