3(2r-1)+r=2(3r+1)

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Solution for 3(2r-1)+r=2(3r+1) equation: 



3(2r-1)+r=2(3r+1)

We move all terms to the left:

3(2r-1)+r-(2(3r+1))=0

We add all the numbers together, and all the variables

r+3(2r-1)-(2(3r+1))=0

We multiply parentheses

r+6r-(2(3r+1))-3=0



We calculate terms in parentheses: -(2(3r+1)), so:

2(3r+1)

We multiply parentheses

6r+2

Back to the equation:

-(6r+2)



We add all the numbers together, and all the variables

7r-(6r+2)-3=0

We get rid of parentheses

7r-6r-2-3=0

We add all the numbers together, and all the variables

r-5=0

We move all terms containing r to the left, all other terms to the right

r=5

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