3(2r+4)-3(r+2)=15

Solution for 3(2r+4)-3(r+2)=15 equation:

Simplifying
3(2r + 4) + -3(r + 2) = 15

Reorder the terms:
3(4 + 2r) + -3(r + 2) = 15
(4 * 3 + 2r * 3) + -3(r + 2) = 15
(12 + 6r) + -3(r + 2) = 15

Reorder the terms:
12 + 6r + -3(2 + r) = 15
12 + 6r + (2 * -3 + r * -3) = 15
12 + 6r + (-6 + -3r) = 15

Reorder the terms:
12 + -6 + 6r + -3r = 15

Combine like terms: 12 + -6 = 6
6 + 6r + -3r = 15

Combine like terms: 6r + -3r = 3r
6 + 3r = 15

Solving
6 + 3r = 15

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3r = 15 + -6

Combine like terms: 6 + -6 = 0
0 + 3r = 15 + -6
3r = 15 + -6

Combine like terms: 15 + -6 = 9
3r = 9

Divide each side by '3'.
r = 3

Simplifying
r = 3