3(2q+1)=q+2(6q-2)

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Solution for 3(2q+1)=q+2(6q-2) equation: 



3(2q+1)=q+2(6q-2)

We move all terms to the left:

3(2q+1)-(q+2(6q-2))=0

We multiply parentheses

6q-(q+2(6q-2))+3=0



We calculate terms in parentheses: -(q+2(6q-2)), so:

q+2(6q-2)

We multiply parentheses

q+12q-4

We add all the numbers together, and all the variables

13q-4

Back to the equation:

-(13q-4)



We get rid of parentheses

6q-13q+4+3=0

We add all the numbers together, and all the variables

-7q+7=0

We move all terms containing q to the left, all other terms to the right

-7q=-7

q=-7/-7

q=1

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