3(2p+14)-28=2(p+15)+12

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Solution for 3(2p+14)-28=2(p+15)+12 equation: 



3(2p+14)-28=2(p+15)+12

We move all terms to the left:

3(2p+14)-28-(2(p+15)+12)=0

We multiply parentheses

6p-(2(p+15)+12)+42-28=0



We calculate terms in parentheses: -(2(p+15)+12), so:

2(p+15)+12

We multiply parentheses

2p+30+12

We add all the numbers together, and all the variables

2p+42

Back to the equation:

-(2p+42)



We add all the numbers together, and all the variables

6p-(2p+42)+14=0

We get rid of parentheses

6p-2p-42+14=0

We add all the numbers together, and all the variables

4p-28=0

We move all terms containing p to the left, all other terms to the right

4p=28

p=28/4

p=7

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