3(2n-4)=(9n+1)+5

Solution for 3(2n-4)=(9n+1)+5 equation:

3(2n-4)=(9n+1)+5

We move all terms to the left:

3(2n-4)-((9n+1)+5)=0

We multiply parentheses

6n-((9n+1)+5)-12=0


We calculate terms in parentheses: -((9n+1)+5), so:

(9n+1)+5

We get rid of parentheses

9n+1+5

We add all the numbers together, and all the variables

9n+6

Back to the equation:

-(9n+6)


We get rid of parentheses

6n-9n-6-12=0

We add all the numbers together, and all the variables

-3n-18=0

We move all terms containing n to the left, all other terms to the right

-3n=18

n=18/-3

n=-6