3(2n-4)+6=9n-5(-n+2)

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Solution for 3(2n-4)+6=9n-5(-n+2) equation: 



3(2n-4)+6=9n-5(-n+2)

We move all terms to the left:

3(2n-4)+6-(9n-5(-n+2))=0

We add all the numbers together, and all the variables

3(2n-4)-(9n-5(-1n+2))+6=0

We multiply parentheses

6n-(9n-5(-1n+2))-12+6=0



We calculate terms in parentheses: -(9n-5(-1n+2)), so:

9n-5(-1n+2)

We multiply parentheses

9n+5n-10

We add all the numbers together, and all the variables

14n-10

Back to the equation:

-(14n-10)



We add all the numbers together, and all the variables

6n-(14n-10)-6=0

We get rid of parentheses

6n-14n+10-6=0

We add all the numbers together, and all the variables

-8n+4=0

We move all terms containing n to the left, all other terms to the right

-8n=-4

n=-4/-8

n=1/2

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