3(2n-3)=4(4n-1)

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Solution for 3(2n-3)=4(4n-1) equation: 



3(2n-3)=4(4n-1)

We move all terms to the left:

3(2n-3)-(4(4n-1))=0

We multiply parentheses

6n-(4(4n-1))-9=0



We calculate terms in parentheses: -(4(4n-1)), so:

4(4n-1)

We multiply parentheses

16n-4

Back to the equation:

-(16n-4)



We get rid of parentheses

6n-16n+4-9=0

We add all the numbers together, and all the variables

-10n-5=0

We move all terms containing n to the left, all other terms to the right

-10n=5

n=5/-10

n=-1/2

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