3(2n-1)-5(n+4)=7(-3n+1)-10

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Solution for 3(2n-1)-5(n+4)=7(-3n+1)-10 equation: 



3(2n-1)-5(n+4)=7(-3n+1)-10

We move all terms to the left:

3(2n-1)-5(n+4)-(7(-3n+1)-10)=0

We multiply parentheses

6n-5n-(7(-3n+1)-10)-3-20=0



We calculate terms in parentheses: -(7(-3n+1)-10), so:

7(-3n+1)-10

We multiply parentheses

-21n+7-10

We add all the numbers together, and all the variables

-21n-3

Back to the equation:

-(-21n-3)



We add all the numbers together, and all the variables

n-(-21n-3)-23=0

We get rid of parentheses

n+21n+3-23=0

We add all the numbers together, and all the variables

22n-20=0

We move all terms containing n to the left, all other terms to the right

22n=20

n=20/22

n=10/11

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