3(2n+3)=9n+4(N-3)

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Solution for 3(2n+3)=9n+4(N-3) equation: 



3(2n+3)=9n+4(-3)

We move all terms to the left:

3(2n+3)-(9n+4(-3))=0

We multiply parentheses

6n-(9n+4(-3))+9=0



We calculate terms in parentheses: -(9n+4(-3)), so:

9n+4(-3)

We add all the numbers together, and all the variables

9n-12

Back to the equation:

-(9n-12)



We get rid of parentheses

6n-9n+12+9=0

We add all the numbers together, and all the variables

-3n+21=0

We move all terms containing n to the left, all other terms to the right

-3n=-21

n=-21/-3

n=+7

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