3(2n+3)=5(n+1)

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Solution for 3(2n+3)=5(n+1) equation: 



3(2n+3)=5(n+1)

We move all terms to the left:

3(2n+3)-(5(n+1))=0

We multiply parentheses

6n-(5(n+1))+9=0



We calculate terms in parentheses: -(5(n+1)), so:

5(n+1)

We multiply parentheses

5n+5

Back to the equation:

-(5n+5)



We get rid of parentheses

6n-5n-5+9=0

We add all the numbers together, and all the variables

n+4=0

We move all terms containing n to the left, all other terms to the right

n=-4

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