3(2n+1)=5(n-2)+15

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Solution for 3(2n+1)=5(n-2)+15 equation: 



3(2n+1)=5(n-2)+15

We move all terms to the left:

3(2n+1)-(5(n-2)+15)=0

We multiply parentheses

6n-(5(n-2)+15)+3=0



We calculate terms in parentheses: -(5(n-2)+15), so:

5(n-2)+15

We multiply parentheses

5n-10+15

We add all the numbers together, and all the variables

5n+5

Back to the equation:

-(5n+5)



We get rid of parentheses

6n-5n-5+3=0

We add all the numbers together, and all the variables

n-2=0

We move all terms containing n to the left, all other terms to the right

n=2

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