3(2m-7)m=-4

Solution for 3(2m-7)m=-4 equation:

3(2m-7)m=-4

We move all terms to the left:

3(2m-7)m-(-4)=0

We add all the numbers together, and all the variables

3(2m-7)m+4=0

We multiply parentheses

6m^2-21m+4=0

a = 6; b = -21; c = +4;
Δ = b2-4ac
Δ = -212-4·6·4
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{345}}{2*6}=\frac{21-\sqrt{345}}{12}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{345}}{2*6}=\frac{21+\sqrt{345}}{12}
$