3(2m-4)+12=4(m+1)

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Solution for 3(2m-4)+12=4(m+1) equation:


Simplifying
3(2m + -4) + 12 = 4(m + 1)

Reorder the terms:
3(-4 + 2m) + 12 = 4(m + 1)
(-4 * 3 + 2m * 3) + 12 = 4(m + 1)
(-12 + 6m) + 12 = 4(m + 1)

Reorder the terms:
-12 + 12 + 6m = 4(m + 1)

Combine like terms: -12 + 12 = 0
0 + 6m = 4(m + 1)
6m = 4(m + 1)

Reorder the terms:
6m = 4(1 + m)
6m = (1 * 4 + m * 4)
6m = (4 + 4m)

Solving
6m = 4 + 4m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-4m' to each side of the equation.
6m + -4m = 4 + 4m + -4m

Combine like terms: 6m + -4m = 2m
2m = 4 + 4m + -4m

Combine like terms: 4m + -4m = 0
2m = 4 + 0
2m = 4

Divide each side by '2'.
m = 2

Simplifying
m = 2

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