3(2m+5)=4(m+2)+m

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Solution for 3(2m+5)=4(m+2)+m equation: 



3(2m+5)=4(m+2)+m

We move all terms to the left:

3(2m+5)-(4(m+2)+m)=0

We multiply parentheses

6m-(4(m+2)+m)+15=0



We calculate terms in parentheses: -(4(m+2)+m), so:

4(m+2)+m

We add all the numbers together, and all the variables

m+4(m+2)

We multiply parentheses

m+4m+8

We add all the numbers together, and all the variables

5m+8

Back to the equation:

-(5m+8)



We get rid of parentheses

6m-5m-8+15=0

We add all the numbers together, and all the variables

m+7=0

We move all terms containing m to the left, all other terms to the right

m=-7

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