3(2m+5)=4(9-m)

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Solution for 3(2m+5)=4(9-m) equation: 



3(2m+5)=4(9-m)

We move all terms to the left:

3(2m+5)-(4(9-m))=0

We add all the numbers together, and all the variables

3(2m+5)-(4(-1m+9))=0

We multiply parentheses

6m-(4(-1m+9))+15=0



We calculate terms in parentheses: -(4(-1m+9)), so:

4(-1m+9)

We multiply parentheses

-4m+36

Back to the equation:

-(-4m+36)



We get rid of parentheses

6m+4m-36+15=0

We add all the numbers together, and all the variables

10m-21=0

We move all terms containing m to the left, all other terms to the right

10m=21

m=21/10

m=2+1/10

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