3(2m+1)=5(m+2)

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Solution for 3(2m+1)=5(m+2) equation: 



3(2m+1)=5(m+2)

We move all terms to the left:

3(2m+1)-(5(m+2))=0

We multiply parentheses

6m-(5(m+2))+3=0



We calculate terms in parentheses: -(5(m+2)), so:

5(m+2)

We multiply parentheses

5m+10

Back to the equation:

-(5m+10)



We get rid of parentheses

6m-5m-10+3=0

We add all the numbers together, and all the variables

m-7=0

We move all terms containing m to the left, all other terms to the right

m=7

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