3(2m)+4(6m+2)=128

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Solution for 3(2m)+4(6m+2)=128 equation: 



3(2m)+4(6m+2)=128

We move all terms to the left:

3(2m)+4(6m+2)-(128)=0

We multiply parentheses

32m+24m+8-128=0

We add all the numbers together, and all the variables

56m-120=0

We move all terms containing m to the left, all other terms to the right

56m=120

m=120/56

m=2+1/7

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