3(2k-5)=66(k-4)+9

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Solution for 3(2k-5)=66(k-4)+9 equation: 



3(2k-5)=66(k-4)+9

We move all terms to the left:

3(2k-5)-(66(k-4)+9)=0

We multiply parentheses

6k-(66(k-4)+9)-15=0



We calculate terms in parentheses: -(66(k-4)+9), so:

66(k-4)+9

We multiply parentheses

66k-264+9

We add all the numbers together, and all the variables

66k-255

Back to the equation:

-(66k-255)



We get rid of parentheses

6k-66k+255-15=0

We add all the numbers together, and all the variables

-60k+240=0

We move all terms containing k to the left, all other terms to the right

-60k=-240

k=-240/-60

k=+4

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