3(2k-5)=4-(3k+7)

Solution for 3(2k-5)=4-(3k+7) equation:

3(2k-5)=4-(3k+7)

We move all terms to the left:

3(2k-5)-(4-(3k+7))=0

We multiply parentheses

6k-(4-(3k+7))-15=0


We calculate terms in parentheses: -(4-(3k+7)), so:

4-(3k+7)

determiningTheFunctionDomain
-(3k+7)+4

We get rid of parentheses

-3k-7+4

We add all the numbers together, and all the variables

-3k-3

Back to the equation:

-(-3k-3)


We get rid of parentheses

6k+3k+3-15=0

We add all the numbers together, and all the variables

9k-12=0

We move all terms containing k to the left, all other terms to the right

9k=12

k=12/9

k=1+1/3