3(2k-5)=15

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Solution for 3(2k-5)=15 equation: 



3(2k-5)=15

We move all terms to the left:

3(2k-5)-(15)=0

We multiply parentheses

6k-15-15=0

We add all the numbers together, and all the variables

6k-30=0

We move all terms containing k to the left, all other terms to the right

6k=30

k=30/6

k=5

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