3(2k-5)=-27

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Solution for 3(2k-5)=-27 equation: 



3(2k-5)=-27

We move all terms to the left:

3(2k-5)-(-27)=0

We add all the numbers together, and all the variables

3(2k-5)+27=0

We multiply parentheses

6k-15+27=0

We add all the numbers together, and all the variables

6k+12=0

We move all terms containing k to the left, all other terms to the right

6k=-12

k=-12/6

k=-2

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