3(2k-5)+5(3k+1)=179

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Solution for 3(2k-5)+5(3k+1)=179 equation: 



3(2k-5)+5(3k+1)=179

We move all terms to the left:

3(2k-5)+5(3k+1)-(179)=0

We multiply parentheses

6k+15k-15+5-179=0

We add all the numbers together, and all the variables

21k-189=0

We move all terms containing k to the left, all other terms to the right

21k=189

k=189/21

k=9

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