3(2k-3)=27

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Solution for 3(2k-3)=27 equation: 



3(2k-3)=27

We move all terms to the left:

3(2k-3)-(27)=0

We multiply parentheses

6k-9-27=0

We add all the numbers together, and all the variables

6k-36=0

We move all terms containing k to the left, all other terms to the right

6k=36

k=36/6

k=6

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