3(2k+4)=3(4k+2)

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Solution for 3(2k+4)=3(4k+2) equation: 



3(2k+4)=3(4k+2)

We move all terms to the left:

3(2k+4)-(3(4k+2))=0

We multiply parentheses

6k-(3(4k+2))+12=0



We calculate terms in parentheses: -(3(4k+2)), so:

3(4k+2)

We multiply parentheses

12k+6

Back to the equation:

-(12k+6)



We get rid of parentheses

6k-12k-6+12=0

We add all the numbers together, and all the variables

-6k+6=0

We move all terms containing k to the left, all other terms to the right

-6k=-6

k=-6/-6

k=1

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