3(2k+3)+2(5-k)=2

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Solution for 3(2k+3)+2(5-k)=2 equation: 



3(2k+3)+2(5-k)=2

We move all terms to the left:

3(2k+3)+2(5-k)-(2)=0

We add all the numbers together, and all the variables

3(2k+3)+2(-1k+5)-2=0

We multiply parentheses

6k-2k+9+10-2=0

We add all the numbers together, and all the variables

4k+17=0

We move all terms containing k to the left, all other terms to the right

4k=-17

k=-17/4

k=-4+1/4

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