3(2k+1)=5(k+2)

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Solution for 3(2k+1)=5(k+2) equation:


Simplifying
3(2k + 1) = 5(k + 2)

Reorder the terms:
3(1 + 2k) = 5(k + 2)
(1 * 3 + 2k * 3) = 5(k + 2)
(3 + 6k) = 5(k + 2)

Reorder the terms:
3 + 6k = 5(2 + k)
3 + 6k = (2 * 5 + k * 5)
3 + 6k = (10 + 5k)

Solving
3 + 6k = 10 + 5k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-5k' to each side of the equation.
3 + 6k + -5k = 10 + 5k + -5k

Combine like terms: 6k + -5k = 1k
3 + 1k = 10 + 5k + -5k

Combine like terms: 5k + -5k = 0
3 + 1k = 10 + 0
3 + 1k = 10

Add '-3' to each side of the equation.
3 + -3 + 1k = 10 + -3

Combine like terms: 3 + -3 = 0
0 + 1k = 10 + -3
1k = 10 + -3

Combine like terms: 10 + -3 = 7
1k = 7

Divide each side by '1'.
k = 7

Simplifying
k = 7

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