3(2iks-5)-4(iks+1)=7

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Solution for 3(2iks-5)-4(iks+1)=7 equation:


Simplifying
3(2iks + -5) + -4(iks + 1) = 7

Reorder the terms:
3(-5 + 2iks) + -4(iks + 1) = 7
(-5 * 3 + 2iks * 3) + -4(iks + 1) = 7
(-15 + 6iks) + -4(iks + 1) = 7

Reorder the terms:
-15 + 6iks + -4(1 + iks) = 7
-15 + 6iks + (1 * -4 + iks * -4) = 7
-15 + 6iks + (-4 + -4iks) = 7

Reorder the terms:
-15 + -4 + 6iks + -4iks = 7

Combine like terms: -15 + -4 = -19
-19 + 6iks + -4iks = 7

Combine like terms: 6iks + -4iks = 2iks
-19 + 2iks = 7

Solving
-19 + 2iks = 7

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '19' to each side of the equation.
-19 + 19 + 2iks = 7 + 19

Combine like terms: -19 + 19 = 0
0 + 2iks = 7 + 19
2iks = 7 + 19

Combine like terms: 7 + 19 = 26
2iks = 26

Divide each side by '2ks'.
i = 13k-1s-1

Simplifying
i = 13k-1s-1

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