3(2h-7)=(2+4h)2

Solution for 3(2h-7)=(2+4h)2 equation:

3(2h-7)=(2+4h)2

We move all terms to the left:

3(2h-7)-((2+4h)2)=0

We add all the numbers together, and all the variables

3(2h-7)-((4h+2)2)=0

We multiply parentheses

6h-((4h+2)2)-21=0


We calculate terms in parentheses: -((4h+2)2), so:

(4h+2)2

We multiply parentheses

8h+4

Back to the equation:

-(8h+4)


We get rid of parentheses

6h-8h-4-21=0

We add all the numbers together, and all the variables

-2h-25=0

We move all terms containing h to the left, all other terms to the right

-2h=25

h=25/-2

h=-12+1/2