3(2h-1)-6=3h-(2h+19)

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Solution for 3(2h-1)-6=3h-(2h+19) equation: 



3(2h-1)-6=3h-(2h+19)

We move all terms to the left:

3(2h-1)-6-(3h-(2h+19))=0

We multiply parentheses

6h-(3h-(2h+19))-3-6=0



We calculate terms in parentheses: -(3h-(2h+19)), so:

3h-(2h+19)

We get rid of parentheses

3h-2h-19

We add all the numbers together, and all the variables

h-19

Back to the equation:

-(h-19)



We add all the numbers together, and all the variables

6h-(h-19)-9=0

We get rid of parentheses

6h-h+19-9=0

We add all the numbers together, and all the variables

5h+10=0

We move all terms containing h to the left, all other terms to the right

5h=-10

h=-10/5

h=-2

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