3(2g-3)+4(3g-5)-7(g-11)=0

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Solution for 3(2g-3)+4(3g-5)-7(g-11)=0 equation: 



3(2g-3)+4(3g-5)-7(g-11)=0

We multiply parentheses

6g+12g-7g-9-20+77=0

We add all the numbers together, and all the variables

11g+48=0

We move all terms containing g to the left, all other terms to the right

11g=-48

g=-48/11

g=-4+4/11

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