3(2f+2)=+6

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Solution for 3(2f+2)=+6 equation: 



3(2f+2)=+6

We move all terms to the left:

3(2f+2)-(+6)=0

We add all the numbers together, and all the variables

3(2f+2)-6=0

We multiply parentheses

6f+6-6=0

We add all the numbers together, and all the variables

6f=0

f=0/6

f=0

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