3(2d-1)-2d=4(d-2+5)

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Solution for 3(2d-1)-2d=4(d-2+5) equation: 



3(2d-1)-2d=4(d-2+5)

We move all terms to the left:

3(2d-1)-2d-(4(d-2+5))=0

We add all the numbers together, and all the variables

3(2d-1)-2d-(4(d+3))=0

We add all the numbers together, and all the variables

-2d+3(2d-1)-(4(d+3))=0

We multiply parentheses

-2d+6d-(4(d+3))-3=0



We calculate terms in parentheses: -(4(d+3)), so:

4(d+3)

We multiply parentheses

4d+12

Back to the equation:

-(4d+12)



We add all the numbers together, and all the variables

4d-(4d+12)-3=0

We get rid of parentheses

4d-4d-12-3=0

We add all the numbers together, and all the variables

-15!=0

There is no solution for this equation

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