3(2d-1)-2d=4(d-2)-5

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Solution for 3(2d-1)-2d=4(d-2)-5 equation:



3(2d-1)-2d=4(d-2)-5
We move all terms to the left:
3(2d-1)-2d-(4(d-2)-5)=0
We add all the numbers together, and all the variables
-2d+3(2d-1)-(4(d-2)-5)=0
We multiply parentheses
-2d+6d-(4(d-2)-5)-3=0
We calculate terms in parentheses: -(4(d-2)-5), so:
4(d-2)-5
We multiply parentheses
4d-8-5
We add all the numbers together, and all the variables
4d-13
Back to the equation:
-(4d-13)
We add all the numbers together, and all the variables
4d-(4d-13)-3=0
We get rid of parentheses
4d-4d+13-3=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation

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